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Display all divisors of a number C++


C++ Display all divisors of a number.

#include <iostream>
using std::cout;
using std::cin;
using std::endl;

int main(){
cout << "Enter a number: "; int num; cin >>num;

for (int i = 2 ; i < num;  i++){
if (num % i == 0){
cout << i << endl;
}
}
return 0;
}

1 comment:

  1. A divisor, also called a factor, of a number is a number which divides that number completely (such that there is no remainder). You are required to write a program that finds the number (in the given range) which has maximum number of divisors. The program first asks the user to input two values P and Q for a range (where p < Q). After that, the program should find a number having highest number of divisors. In the end, the program should print that numbers (having highest number of divisors) along its divisor count.
    Sample Inputs:
    Enter first number (P): 1
    Enter second number (Q): 10
    Sample Output: 6 has maximum of 4 divisors.(help me making this one)

    ReplyDelete

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